x^2+(1/3)x-(1/6)=0

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Solution for x^2+(1/3)x-(1/6)=0 equation: 


x in (-oo:+oo)

x^2+(1/3)*x-(1/6) = 0

x^2+(1/3)*x-1/6 = 0

x^2+1/3*x-1/6 = 0

DELTA = (1/3)^2-(-1/6*1*4)

DELTA = 7/9

DELTA > 0

x = ((7/9)^(1/2)-1/3)/(1*2) or x = (-(7/9)^(1/2)-1/3)/(1*2)

x = ((7/9)^(1/2)-1/3)/2 or x = (-((7/9)^(1/2)+1/3))/2

x in { (-((7/9)^(1/2)+1/3))/2, ((7/9)^(1/2)-1/3)/2 }

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